Current through a coil of self-inductance 10 mH is changing with time as `i =(4t^(2) + 2t+2)` A, wheret is in second. Find the induced emf developed in the coil att = 2 s.

Explanation

Here, `L = 10 mH = 10 xx 10^(-3) = 10^(-2)H `
`i =(4t^(2) + 2+ + 2) A`
`:. (di)/(dt) = (8t +2)A `
`((di)/(dt))_(t=2s)=(8xx2 +2) = 18V`
Induced emf developed, `epsilon=L (di)/(dt)=10^(-2)(18)`
= 0.18 V