The maximum peak to peak voltage of an AM wave is 20 mV. If the modulation index is 50%, find the minimum peak to peak voltage.

Explanation

Here , modulation index , `mu = 50% = 1/2`
Maximum voltage , `V_("max") = 20 mV`
Minimum voltage , `V_("min") =?`
As, modulation index, `mu =(V_("max")- V_("min"))/(V_("max")+ V_("min"))`
`1/2 =(20-V_("min"))/(20+v_("min"))`
`implies 20+ V_("min") = 2(20-V_("min"))`
`implies 20 + V_("min") = 40 - 2V_("min")`
`implies 3V_("min") = 20`
`implies V_("min") = (20)/(3) = 6.67 mV`