A solenoid, of length 1.0 m, has a radius of 1 cm and has a total of 11-2 1000 turns wound on it. It carries a current of 5 A. Calculate the magnitude of the axial magnetic field inside the solenoid. If an 1A+ electron was to move with a speed of `10^(4)` m/s along the axis of this current carrying solenoid, what would be the force experienced by this electron?

Explanation

Given length L =1 m radius r =1 cm = 0.01 m Number of turns N=1000 l =5 A
`:.` Magnetic fiel P inside the solenoid
`B = mu_(0)nl = mu_(0) ((N)/(L))l " " [ n= (N)/(L)]`
`= mu_(0) ((1000)/(1)) xx 5`
`= mu_(0) ((1000)/(1))xx 5`
`= 4pi xx 10^(-7) xx 1000 xx 5 `
`B =2pi xx 10^(-3)` T
The direction of B is along the axis of solenoid Now q=-e , v = `10^(4)` m/s and the angle between B and v is `0^(@)`
[ electron moven along the direction of magnetic field ]
`:.` Lorentz force
`F_(B) =eq B sin 0^(@) = qv B xx 0=0`
`F_(B)= 0`
` implies ` No magnetic force experience by the electron .