Home
Class 12
CHEMISTRY
Formation of polyethylene from calcium c...

Formation of polyethylene from calcium carbide takes place as follows
`CaC_(2)+2 H_(2)O rarr Ca(OH)_(2)+C_(2)H_(2)`
`C_(2)H_(2)+H_(2) rarr C_(2)H_(2)`
`N(C_(2)H_(4)) rarr (-CH_(2)-CH_(2)-)_(n)`
The amount of polyethylene obtained from `64.1 kg CaC_(2) ` is

A

`7 kg `

B

14 kg

C

21 kg

D

28 kg

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • QUESTION-PAPERS-2015

    BITSAT GUIDE|Exercise CHEMISTRY |40 Videos

  • QUESTION-PAPERS-2017

    BITSAT GUIDE|Exercise CHEMISTRY |40 Videos

Similar Questions

Explore conceptually related problems

Formation of polyethylene from calcium carbide takes place as follows CaC_(2)+2H_(2)OrarrCa(OH)_(2)_C_(2)H_(2) C_(2)H_(2)+H_(2)rarrC_(2)H_(4) n(C_(2)H_(4))rarr(-CH_(2)-CH_(2)-)_(n) The mass of polyethylene obtained in kg from 64 kg CaC_(2) is

Polyethylene is obtained from calcium carbide. CaC_(2)+2H_(2)Orarr Ca(OH)_(2)+C_(2)H_(2) C_(2)H_(2)+H_(2)rarr C_(2)H_(4) nC_(2)H_(4)rarr (-CH_(2)-CH_(2)-)n Therefore, the amount of polyethylene (in kg) obtained for 64 kg CaC_(2) is

Knowledge Check

  • Formation of polythene from calcium carbide takes place as follows CaC_(2)+2H_(2)OrarrCa(OH)_(2)+C_(2)H_(2) C_(2)H_(2)+H_(2)rarrC_(2)H_(4) nC_(2)H_(4) to (-CH_(2) -CH_(2)-)_(n) The amount of polythene obtained from 64 kg of CaC_(2) is

    A
    7 kg
    B
    14 kg
    C
    21 kg
    D
    28 kg

  • Formation of polyethylene from calcium carbide takes place as follows CaC_2+2H_2O to Ca(OH)_2 +C_2H_2 C_2H_2 +H_2 to C_2H_4 n(C_2H_4) to (-CH_2-CH_2-)_n The amount of polyethylene obtained from 64.1 kg CaC_2 is

    A
    7 kg
    B
    14 kg
    C
    21 kg
    D
    28 kg

  • Polythylene is obtained from calcium cabide . CaC_(2) +2H_(2)O to Ca(OH)_(2)+C_(2)H_(5) C_(2)H_(2)+H_(2) to C_(2)H_(4) nC_(2)H_(4) to (--CH_(2)-CH_(2)--)_(n) Therefore , the amount of polyethylen obtained for 64 kg CaC_(2) is

    A
    7 kg
    B
    14 kg
    C
    21 kg
    D
    28 kg

    • Similar Questions

    Explore conceptually related problems

    From the following reaction sequence, {:(CaC_(2) + H_(2) O to CaO+ C_(2)H_(2)),(" "C_(2)H_(2)toC_(2)H_(4)),(" "nC_(2)H_(4) to (C_(2)H_(4))_(n)):} calculate the mass of polyethylene which can be produced from 10 kg of CaC_(2)

    The fomation of polyethylene from calcium carbide takes place as follows: CaC_(2)+2H_(2)OrarrCa(OH_(2))+C_(2)H_(2) C_(2)H_(2)+H_(2)rarrC_(2)H_(4) The amount of polyethylene obtained form 64kg of CaC_(2)

    Formation of polythene from calcium carbide takes place as follows CaC_2 + 2H_2O to Ca(OH)_2 + C_2H_2 C_2H_2 + H_2 to C_2H_4 nC_2H_4 to (-- CH_2 - CH_2 --)_n The amount of poolythene obtaine from 64 kg of CaC_2 is

    Polythene can be produced from calcium carbide according to the following sequence of reactions. CaC_(2)+2H_(2)Orarr Ca(OH)_(2)+C_(2)H_(2), C_(2)H_(2)+H_(2)rarr C_(2)H_(4), nC_(2)H_(4)rarr(C_(2)H_(4))n The mass of polythene which can be produced from "20.0 kg of "CaC_(2) is :

    The formulation of polyethene from calcium carbide takes place as follows: CaC_2+2H_2OtoCa(OH)_2+C_2H_2 C_2H_2+H_2toC_2H_6 nC_2H_6to-(CH_2-CH_2)-_n The amount of polythene obtained from 64 kg of CaC_2 is

    Home
    Profile