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Formation of polyethylene from calcium c...

Formation of polyethylene from calcium carbide takes place as follows
`CaC_(2)+2 H_(2)O rarr Ca(OH)_(2)+C_(2)H_(2)`
`C_(2)H_(2)+H_(2) rarr C_(2)H_(2)`
`N(C_(2)H_(4)) rarr (-CH_(2)-CH_(2)-)_(n)`
The amount of polyethylene obtained from `64.1 kg CaC_(2) ` is

A

`7 kg `

B

14 kg

C

21 kg

D

28 kg

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The correct Answer is:
D
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Formation of polyethylene from calcium carbide takes place as follows CaC_(2)+2H_(2)OrarrCa(OH)_(2)_C_(2)H_(2) C_(2)H_(2)+H_(2)rarrC_(2)H_(4) n(C_(2)H_(4))rarr(-CH_(2)-CH_(2)-)_(n) The mass of polyethylene obtained in kg from 64 kg CaC_(2) is

The fomation of polyethylene from calcium carbide takes place as follows: CaC_(2)+2H_(2)OrarrCa(OH_(2))+C_(2)H_(2) C_(2)H_(2)+H_(2)rarrC_(2)H_(4) The amount of polyethylene obtained form 64kg of CaC_(2)

Polythene can be produced from calcium carbide according to the following sequence of reactions. CaC_(2)+2H_(2)Orarr Ca(OH)_(2)+C_(2)H_(2), C_(2)H_(2)+H_(2)rarr C_(2)H_(4), nC_(2)H_(4)rarr(C_(2)H_(4))n The mass of polythene which can be produced from "20.0 kg of "CaC_(2) is :

The formulation of polyethene from calcium carbide takes place as follows: CaC_2+2H_2OtoCa(OH)_2+C_2H_2 C_2H_2+H_2toC_2H_6 nC_2H_6to-(CH_2-CH_2)-_n The amount of polythene obtained from 64 kg of CaC_2 is

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