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Electrolysis is carried out in three cel...

Electrolysis is carried out in three cells
(A) 1.0 M `CuSO_4` Pt electrode
(B) 1.0 M `CuSO_4` copper electrodes
(C) 1.0 M KCl Pt electrodes
If volume of electrolytic solution is maintained constant in each of the cell, which is correct set of pH changes in (A), (B) and (C) cell respectively?

A

decrease in all the three

B

increase in all the three

C

decrease, constant, increase

D

increase, constant, increase

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The correct Answer is:
To solve the problem regarding the pH changes during the electrolysis in the three cells, we will analyze each cell step by step. ### Step 1: Analyze Cell A (1.0 M CuSO4 with Pt Electrode) - **At the Cathode:** The reduction reaction occurs where Cu²⁺ ions gain electrons to form copper metal (Cu). - Reaction: Cu²⁺ + 2e⁻ → Cu - **At the Anode:** Water is oxidized, producing hydrogen ions (H⁺) and oxygen gas (O₂). - Reaction: 2H₂O → O₂ + 4H⁺ + 4e⁻ **Effect on pH:** - The generation of H⁺ ions increases the acidity of the solution, leading to a decrease in pH. ### Step 2: Analyze Cell B (1.0 M CuSO4 with Copper Electrodes) - **At the Cathode:** The reduction of Cu²⁺ ions occurs, similar to Cell A. - Reaction: Cu²⁺ + 2e⁻ → Cu - **At the Anode:** Copper from the anode dissolves into the solution as Cu²⁺ ions. - Reaction: Cu → Cu²⁺ + 2e⁻ **Effect on pH:** - There is no net change in H⁺ or OH⁻ ions in the solution because the amount of Cu²⁺ produced at the anode is equal to the amount consumed at the cathode. Therefore, the pH remains constant. ### Step 3: Analyze Cell C (1.0 M KCl with Pt Electrode) - **At the Cathode:** Water is reduced, producing hydrogen gas and hydroxide ions (OH⁻). - Reaction: 2H₂O + 2e⁻ → H₂ + 2OH⁻ - **At the Anode:** Chloride ions (Cl⁻) are oxidized to chlorine gas (Cl₂). - Reaction: 2Cl⁻ → Cl₂ + 2e⁻ **Effect on pH:** - The generation of OH⁻ ions increases the basicity of the solution, leading to an increase in pH. ### Summary of pH Changes - **Cell A (Pt Electrode in CuSO4):** pH decreases (due to increase in H⁺). - **Cell B (Cu Electrodes in CuSO4):** pH remains constant (no net change in H⁺ or OH⁻). - **Cell C (Pt Electrode in KCl):** pH increases (due to increase in OH⁻). ### Final Answer The correct set of pH changes in cells A, B, and C respectively is: **Decreases, Constant, Increases.**
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