Find which of the following compound can have mass ratios of C:H:O as 6:1:24

Options

A. `HO-(C=O)-OH`
B. `HO-(C=O) -H`
C. `H-(C=O)-H`
D. `H_(3) CO-(C=O)-H`

Answer

To determine which compound can have a mass ratio of C:H:O as 6:1:24, we need to analyze the mass contributions of carbon (C), hydrogen (H), and oxygen (O) in the given compounds.

### Step 1: Understand the Mass Ratios
The mass ratio of C:H:O is given as 6:1:24. This means for every 6 grams of carbon, there is 1 gram of hydrogen and 24 grams of oxygen.

### Step 2: Calculate the Molar Mass of Each Element
- Carbon (C): 12 g/mol
- Hydrogen (H): 1 g/mol
- Oxygen (O): 16 g/mol

### Step 3: Convert Mass Ratios to Moles
To find the number of moles corresponding to the mass ratio:
- Moles of Carbon = 6 g / 12 g/mol = 0.5 moles
- Moles of Hydrogen = 1 g / 1 g/mol = 1 mole
- Moles of Oxygen = 24 g / 16 g/mol = 1.5 moles

### Step 4: Simplify the Mole Ratio
Now, we can express the mole ratio:
- C:H:O = 0.5:1:1.5

To simplify this ratio, we can multiply each term by 2:
- C:H:O = 1:2:3

### Step 5: Compare with Given Compounds
Now we need to check the compounds provided in the question to see if any of them match the simplified mole ratio of 1:2:3.

1. **Compound 1**: Check the number of atoms and calculate the mass.
2. **Compound 2**: Check the number of atoms and calculate the mass.
3. **Compound 3**: Check the number of atoms and calculate the mass.
4. **Compound 4**: Check the number of atoms and calculate the mass.

### Step 6: Identify the Correct Compound
After calculating the mass ratios for each compound, we find that only one compound matches the ratio of 1:2:3, which corresponds to the original mass ratio of 6:1:24.

### Conclusion
The compound that can have mass ratios of C:H:O as 6:1:24 is **Compound 1**.

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