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What should be the velocity of earth due...

What should be the velocity of earth due to rotation about its own axis so that the weight at equator become 3/5 of initial value. Radius of earth on equator is 6400 km

A

`8.7 xx 10^(-1)` rad/s

B

`7.8 xx 10^(-4)` rad/s

C

`6.7xx 10^(-4)` rad/s

D

`7.4xx 10^(-3)` rad/s

Text Solution

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The correct Answer is:
B
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What should be the angular velocity of rotation of Earth about its own axis so that the weight of body at the equator reduces to 3/5 of its present value? (Take R as the radius of the Earth)

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Knowledge Check

  • What should be the angular velocity of earth about its own axis so that the weight of the body at the equator would become 3/4 th of its present value ?

    A
    `1/400 rads^(-1)`
    B
    `1/800 rad s^(-1)`
    C
    `1/1600 rad s^(-1)`
    D
    `1/3200 rad s^(-1)`
  • Find the value of angular velocity of axial rotation of the earth, such that weight of a person at equator becomes 3/4 of its weight at pole, Radius of the earth at equator is 6400 km.

    A
    `62xx10^(-4)"rads"^(-1)`
    B
    `52xx10^(-4)"rads"^(-1)`.
    C
    `62xx10^(-2)"rads"^(-1)`.
    D
    NONE OF THE ABOVE
  • The value of angular momentum of the earth rotating about its own axis is

    A
    `7xx10^(33) kg m^(2)//s`
    B
    `7xx10^(33) kg m^(2)//s`
    C
    `0.7xx10^(33) kg m^(2)//s`
    D
    zero
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    What should be the length of the day so that the weight of a body on the equator of earth becomes zero ? Given that radius of earth is 6400 km and acceleration due to gravity on its surface is 9.8 m//s^(2)

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