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Given vec P =2 hati -3 hatj +4 hatk and ...

Given `vec P =2 hati -3 hatj +4 hatk and vec Q= hatj-2 hatk`. The magnitude of their resultant is

A

`sqrt(3)`

B

`2sqrt(3)`

C

`3sqrt(3)`

D

`4sqrt(3)`

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The correct Answer is:
To find the magnitude of the resultant vector \(\vec{R}\) formed by the vectors \(\vec{P}\) and \(\vec{Q}\), we will follow these steps: ### Step 1: Write down the given vectors We have: \[ \vec{P} = 2 \hat{i} - 3 \hat{j} + 4 \hat{k} \] \[ \vec{Q} = 0 \hat{i} + 1 \hat{j} - 2 \hat{k} \] ### Step 2: Add the vectors to find the resultant vector \(\vec{R}\) To find the resultant vector \(\vec{R} = \vec{P} + \vec{Q}\), we add the corresponding components of \(\vec{P}\) and \(\vec{Q}\): - The \(i\) component: \(2 + 0 = 2\) - The \(j\) component: \(-3 + 1 = -2\) - The \(k\) component: \(4 - 2 = 2\) Thus, the resultant vector \(\vec{R}\) is: \[ \vec{R} = 2 \hat{i} - 2 \hat{j} + 2 \hat{k} \] ### Step 3: Calculate the magnitude of the resultant vector \(\vec{R}\) The magnitude of a vector \(\vec{R} = a \hat{i} + b \hat{j} + c \hat{k}\) is given by: \[ |\vec{R}| = \sqrt{a^2 + b^2 + c^2} \] For our resultant vector \(\vec{R} = 2 \hat{i} - 2 \hat{j} + 2 \hat{k}\): - \(a = 2\) - \(b = -2\) - \(c = 2\) Now, substituting these values into the magnitude formula: \[ |\vec{R}| = \sqrt{(2)^2 + (-2)^2 + (2)^2} \] \[ |\vec{R}| = \sqrt{4 + 4 + 4} = \sqrt{12} = 2\sqrt{3} \] ### Final Answer The magnitude of the resultant vector \(\vec{R}\) is: \[ |\vec{R}| = 2\sqrt{3} \]
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