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The equation of the base BC of an equila...

The equation of the base BC of an equilateral `Delta`ABC is x + y = 2 and A is (2, - 1). The length of the side of the triangle is

A

`sqrt2`

B

`(3/2)^(1/2)`

C

`(1/2)^(1/2)`

D

`(2/3)^(1/2)`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • If the equation of the base of an equilateral triangle is x + y = 2 and the vertex is (2, -1), then the length of the side of the triangle is (in unit)

    A
    `sqrt(2/3)`
    B
    `sqrt(3/2)`
    C
    `sqrt(1/2)`
    D
    `sqrt(5/6)`
  • In an equilateral Delta ABC if AD_|_BC , then

    A
    `2AB^2 = 3AD^2`
    B
    `3AB^2 = 4AD^2`
    C
    `5AB^2 = 6AD^2`
    D
    `4AB^2=5AD^2`
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