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If 4^n/(n+1) lt ((2n)!)/((n!)^2), then P...

If `4^n/(n+1) lt ((2n)!)/((n!)^2)`, then P(n) is true for

A

`n ge 1`

B

`n gt 0`

C

`n lt 0`

D

` n ge 2`

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The correct Answer is:
D
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