Estimate the number of free electrons in 1 g of water and the negative charge possessed by the. Given that Avogadro number `= 6.02 xx 10^23` and molecular weight of water = 18

Calculate the total number of atoms in 18g of water.

Assme that each of copper atom has one free electron estimate the number of free electrons in 1 mg of copper. Given that atomic weight of copper 63.5 and Avogadro number = 6.02 xx 10^23 . What is the charge possessed by these free electrons?

Calculate the total number of electrons present in 1.6g of methane.

Surface tension is exhibited by liquids due to force of attraction between molecules of the liquid. The surface tension decreases with increase in temperature and vanishes at boiling point. Given that the latent heat of vaporation for water rho_(w) = 540kcal/kg ,mechanical equivalent heat =4.2j/cal Avogadro's No. N_A = 6.0 xx 10^26 , and the molecular weight of water M_A = 18 kg for 1 k mole. Estimate the energy required for oe molecule of water to evaporate.

What is the amount of charge possessed by 1 kg of electrons? Given that mass of an electron is 9.1 xx 10^31 kg .

The usual form of the number 3.02 xx 10^(-6) is :

What is the drift velocity of electrons in a silver wire of length 1 m, area of cross-section 3.14 xx 10^-6m^2 and carrying a current of 10 A. Given, charge on electron = 1.6 xx 10^-19C , Avogadro number = 6.02 xx 10^23 atomic weight of silver = 108 and density of silver = 10.5 xx 10^3 kg m^-3 .

A copper atom consists of copper nucleus surrounded by 29 electrons. The atomic weight of copper is 63.5mol e^(-1) . Let us now take two pieces of copper each weighing 10g. Let us trandfer one elcetron from one piece to another for every 100 atoms in that piece. What will be the Coulomb force between the two pieces after the trandfer of electrons, if they are 1cm apart? Avogadro number= 6xx10^(23) mol e^(-1) , charge on an electron =- 1.6xx10^(-19)C.

Calculate the number of molecules in a drop of water weighing 0.05g (H=1, O= 16)

Calculate the momentum of electrons if their wavelength is 2 overset @A . Given that Plank.s constant, h = 6.629 xx 10^9-34) Js, mass of electrons, m=9.1 xx 10^(31) kg.