The electric field components due to a charge inside the cube of side 0.1 m are as shown in the figure.
`E_X = ax,` where a = 500 `NC^-1m^-1E = 0 and E_2 = 0` Calcualte the charge inside the cube.

The electric field components due to a charge inside the cube of side 0.1 m are as shown in the figure. E_X = ax, where a = 500 NC^-1m^-1E_y = 0 and E_z = 0 Calcualte the electric flux through the cube

The electric field at a point due to a point charge is 20NC^-1 and the electric potential at the point is 10JC^-1 Calculate the distance of the point from the charge and the magnitude of the charge.

Consider an arbitrary electrostatic field configuration. A small test charge is placed at a null point (i.e., where E = 0) of the configuration. Show that the equilibrium of the test charge is necessarily unstable.

The electric potential at 0.1m from a point charge is 90V. What is the magnitude of the charge? Given, epsilon_0=8.854xx10^-12 C^2 N^-1 m^-2

In figure the electric field is directed along positive X-direction and given by E_x = 5A x + 2B where E is in NC^-1 and x is in metre. A and B are constants with dimensions. Takign A = 10 N c^-1 m^-1 and B = 5 N C^-1 calculate the electric flux through the cube. and net charge enclosed within the cube.

The electric field E due to any point charge is defined as E=underset (q rarr 0)lim F/q , while q is the test charge and F is the force acting on it. What is the physical signification of underset (q rarr 0)lim in this expression?

The electric potential at 0.3m from a point charge is 30V. What is the magnitude of the charge? Given epsilon_0=8.854xx10^-12 C^2 N^-1 m^-2