Assume that earth has a charge of surface density 1 electron per `metre^3`. Calculate the earth's electric field

Assume that earth has a charge of surface density 1 electron per metre^2 . Calculate the earth's electric potential just outside the earth's surface.

A uniformly charged conducting sphere of 2.5 m in diameter has a surface charge density of 100 muC/m^2 . Calculate the total electric flux passing through the sphere.

What will be the corresponding expression for the energy needed to completely diassemble the planet earth against the gravitational pull amongst its constituent particles? Assume the earth to be a sphere of uniform mass density. calculate the energy, given that the product of the mass and the radius of the earth to be 2.5xx10^(31)kg-m

An electron above the earth is balanced by the gravitational force and the electric field of the earth. Find the electric field of the earth.

Calculate the mass and charge of 1 mole of electrons.

Consider the charge configuration and a spherical Gaussian surface as shown in the figure. When calculating the flux of the electric field over the spherical surface, the electric field will be due to.

A uniformly charged conducting sphere of 2.5 m in diameter has a surface charge density of 100 muC/m^2 . Calculate the charge on the sphere.

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux f is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field The electric field at a point is

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux f is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field We have a Gaussian of radius R with Q at the centre then

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux phi is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field. phi=ointvecE.vec(ds)=q/epsilon_0 The electric field at a point is