Assume that earth has a charge of surface density 1 electron per `metre^2`. Calculate the earth's electric potential just outside the earth's surface.

Assume that earth has a charge of surface density 1 electron per metre^3 . Calculate the earth's electric field

What will be the corresponding expression for the energy needed to completely diassemble the planet earth against the gravitational pull amongst its constituent particles? Assume the earth to be a sphere of uniform mass density. calculate the energy, given that the product of the mass and the radius of the earth to be 2.5xx10^(31)kg-m

A spherical conductor of radius 12 cm has a charge of 1.6 xx 10^-7C distributed uniformly on its surface. What is the electric field just outside the sphere?

The earth’s surface has a negative surface charge density of 10^-9 C m^-2 . The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralise the earth’s surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth = 6.37 xx 10^6 m .)

If the earth has net charge that is not zero. Is it possible to adopt the earth as a standard reference point of potential and assign the potential V = 0 to it?

Assuming the earth to be a sphere of radius 6370 km, how many square kilometers is area of the land, if three-fourth of the earth’s surface is convered by water.