Two parallel plates are 5 cm apart and a potential difference of 6- V is set up across them. Find the electric field intensily between the two plates.

A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an isulating handle. As a result the potential difference between the plates

What is the potential difference between two points in the electric field? Name its SI unit.

The plates of a parallel plate capacitor are 50m^2 and one mm apart apart when it is connected to a 45 V battery what is the electric field between the plates?

A small particle carrying a negative charge of 1.6xx10^-19 C is suspended in equilibrium between the horizontal metal plates 5 cm apart, having a potential difference of 3000 volt across them. Find the mass of the particle.

Two charges of values 50muC and 100muC are placed at a distance of 6 cm apart. Find the field and potential at a distance of 6 cm apart. Find the field and potential at a point(between two charges) 2 cm from the charge of value 50 muC .

A parallel capacitor has capacitance 20muF . A potential difference of 220 V is applied across it. Calculate the charge on the plates and energy stored in the capacitor. If a dieletric slab of dielectric constant 5 is introduced between its plates, calculate the new value of potential difference and the energy stored.

On charging a parallel plate capacitor to a potential V, the spacing between the plates is halved and a dielectric medium of k = 10 is introduced between the plates, without disconnectign the d.c. source. Explain, using the suitable expressions, how the electric field

On charging a parallel plate capacitor to a potential V, the spacing between the plates is halved and a dielectric medium of k = 10 is introduced between the plates, without disconnectign the d.c. source. Explain, using the suitable expressions, how the capacitance

On charging a parallel plate capacitor to a potential V, the spacing between the plates is halved and a dielectric medium of k = 10 is introduced between the plates, without disconnectign the d.c. source. Explain, using the suitable expressions, how the energy density of the capacity of change.

A parallel plate capacitor is charged to a potential difference V by a d.c. source. The capacitor is then disconnected from the source. If the distance between the plates is doubled, state with reason how the following will change. electric field between the plates