The equipotential surfaces of a certain electric field are shown in the fig.
It is known that `V_1> V_2`. Use this pattern to reproduce approximately the lines of force of this field. Also indicate the region in which the intensity of the electric field is highest.

Angle between equipotential surface and electric field line of force is:

Two point charges 4Q and Q are separated by a distance of 1 m in air. At what point on the line joining the two charges is the electric field intensity zero?

Work done to move a charge along a closed path inside an electric field is always zero. Use this fact to prove that it is impossible to produce an electric field in which all the lines of force would be parallel straight lines and the density of their distribution would constantly increase in a direction perpendicular to the lines of force as shown in Figure.​

A potential barrier of 0.3 V exists across a P-N junction: If the depletion region is 3 xx10^(-7) m wide , what is the intensity of the electric field in this region?

Two identical plane metallic surfaces A and B are parallel to each other in air separated by a distance of 1 cm as shown in the fig. Surface A is given a postive potential 10 V and the outer surface of B is earthend What is the magnitude and direction of the uniform electric field between points Y and Z?

A distance of 2 m separates two point charges of +5 xx 10^-19C . Find the point on the line joining them at which electric field intensity is zero.

Define equipotential surfaces. Show that in the region of strong electric fields, equipotential surfaces are close together and in the regions of weaker fields, they are far apart.

There is a set of lines of force which converge as we go from left to right. The electric field is stronger on: