In a parallel plate capacitor, how is the capacitance affected, when without changing the charge,area of the plate is halved.

In a parallel plate capacitor, how is the capacitance affected, when without changing the charge, the distance between the plates is doubled.

Derive an expression for the capacitance of a parallel plate capacitor. How is the capacitance affected when a conducting slab is introduced in-between its plates? Explain

A parallel plate capacitor is charged. If the plates are pulled apart

How would you modify 5.0 nF parallel plate capacitor storing 25.0 J of energy so that it can store 50.0 J of energy without changing the charge on its plates?

If a parallel plate capacitor of capacitance C is kept connected to a supply voltage V and then to just fill the space, dielectric slab is inserted between the plates. What will be the change in the capacitance the charge, the potential difference, the electric field and the energy stored?

Show that during the charging of parallel plate capacitor,the rato of charging of a prallel plate capacitor,the rate of change of charge on each plate equals epsilon_0 times the rate of change of electric flux (phi_E) linked with it .What is the name given to the term epsilon_0 (dphi _E)/(dt) ?

Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (1/2) QE, where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor 1/2.

The force between the plates of a parallel plates capacitor of area A, capacitance C and having charge of will be