If a parallel plate capacitor of capacitance C is kept connected to a supply voltage V and then to just fill the space, dielectric slab is inserted between the plates. What will be the change in the capacitance the charge, the potential difference, the electric field and the energy stored?

A capacitor with a capacitane of 50muF is connected to 200V, if the distance between its plates is halved, what will be the potential between the plates and what will be the change in energy stored in it?

A parallel plate capacitor has a capacitance of 2muF . A slab of dielectric constant 5 is inserted between the plates and the capaitor is charged to 100 V and then isolated. What is the new potential difference, if the dielectric slab is removed?

In a parallel plate capacitor, the capacitance increases from 4 muF to 80muF no introduicng a dielectric medium between the plates. What is the dielectric constant of the medium?

In a parallel plate capacitor, how is the capacitance affected, when without changing the charge,area of the plate is halved.

Explain why the capacitance of capacitor increases when dieslectric slab is inserted between plates of the capacitor.

Explain why the capacitance of capacitor increases when dieslectric slab is inserted between plates of the capacitor.

A parallel plate capacitor of capacitance C is connected to a battery and is charged to a potential difference V. Another capacitor of capacitance 2C is ismilarly charged to a potential difference 2V. The charging battery is now disconnected and the capacitors are connected in parallel to each other in such a way that the poistive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is