A parallel plate capacitor thas plates of are `0.02m^2 ` and separation between the plates 1 mm. What potential difference will be developed, if a charge of 1nC is given to the capacitor ? If the plate separation is now increased to 2 mm, what will be the new potential difference?

Calculate the area of plates of a capacitor of capacity 2muF , with separation 1.77 mm between the plates.

Calculate the area of plates of a capacitor of capacity 2muF , with separation 1.77 mm between the plates.

A parallel plate capacitor has two plates of sides 0.055 m and 0.04 m of air. Their distance apart is 0.7 mm. The dielectric constant of the medium in between is 4. Find the capacitance of the capacitor.

In a parallel plate capacitor with air between the plates, each plate has an area of 6 xx 10^-3 m^2 and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100 V supply, what is the charge on each plate of the capacitor?

A parallel-plate capacitor having plate are 100 cm ^2 and separation 1.0 mm holds a charge of 0.12 muC when connected to a 120 V battery. Find the dielectric constant of the material filling the gap.

A capacitor of plate area A and separation between plates d is half filled with dielectric of dielectric constant K. What is equivalent capacitance?

In a parallel plate capacitor with air between the plates, each has an area of 6xx10^-3m^-2 and the distance between the platesw is 3mm. Calculate the capacitance of the capacitor, If this capacitor is Connected to 100 V supply, what is the charge on each plate of the capacitor? (Given varepsilon_0=8.5xx10^-12C^2N^-1m^-2)

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in electric field intensity between the plates.

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in charge on plates?