A parallel plate capacitor with plate separation 5 mm is charged by a battery. It is found that on introducing a mica sheet 2 mm thick, while keeping the battery connections intact, the capactor draws 25% more charge from the battery than before. Find the dielectric constant of mica.

A parallel plate capacitor is maintained at a certain potentail difference. When a 3mm thick slab is intorduced between the plate, in a order to maintain the same potential difference, the distance between the plates is increased by 2.4 mm. Find the dielectric constant of the slab.

A parallel-plate capacitor having plate are 100 cm ^2 and separation 1.0 mm holds a charge of 0.12 muC when connected to a 120 V battery. Find the dielectric constant of the material filling the gap.

A parallel plate capacitor of plate area A and plate separation d is charged to potential difference V and then the battery is disconnected. A slab of dielectric constant K is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q, E and W denote respectively, the magnitude of charge on each plate, the electric field between the plates (after the slab is inserted), and work done on the system, in question, in the process of inserting the slab,

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in charge on plates?

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in electric field intensity between the plates.

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in capacitance?

A parallel plate capacitor having area 25 cm^2 and separation 1.00 mm is Connected to a battery of 6.0 V. Calculate the charge flown through the battery. How much work has been done by the battery during this process? (Given varepsilon_0=8.85xx10^-12C^2N^-1m^-2)

A parallel plate capacitor having area 25 cm^2 and separation 1.00 mm is Connected to a battery of 6.0 V. Calculate the charge flown through the battery. How much work has been done by the battery during this process? (Given varepsilon_0=8.85xx10^-12C^2N^-1m^-2)