A parallel plate capacitor a air between its plates having plate area of 6*10^-3 m^2 and separation between them 3 mm is connected to a 100 V battery. Explain what would happen when a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates, while the voltage supply remained connected.

A parallel plate capacitor a air between its plates having plate area of 6*10^-3 m^2 and separation between them 3 mm is connected to a 100 V battery. Explain what would happen when a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates, after the supply was disconnected.

A parallel-plate capacitor having plate are 100 cm ^2 and separation 1.0 mm holds a charge of 0.12 muC when connected to a 120 V battery. Find the dielectric constant of the material filling the gap.

A parallel plate capacitor with air between the plates has a capacitance of 8 pF.What will be the capacitance if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant 5?

A parallel plate capacitor with air between the plates has a capacitance of 8 pF. The separation between the plates is now reduced by half and the space between them is filled with a medium of dielectric constant K. Calculate the value of the capacitance of the capacitor in the second case.

The plates of a parallel plate capacitor are 50m^2 and one mm apart apart when it is connected to a 45 V battery what is the electric field between the plates?

A parallel plate capacitor with air between the plates has capacitance of 9pF. The separation between its plates is 'd'. The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant k_1=3 and thickness d/3 while the other one has dielectric constant k_2=6 and thickness (2d)/(3) . Capacitance of the capacitor is now

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in charge on plates?

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in capacitance?