It is found that 125 cm length of a potentiometer wire is required to balance the e.m.f. of a Daniel cell but that only 100 cm of the wire is required for the balance, if the poles of the ell are joined to a resistance of 2 ohm. Calculate the internal resistance of the cell.

A cell can be balanced against 110 cm and 100 cm of potentiometer wire respectively, when open icrcuited and when short circuited through a resistance of 10 ohm. Find the internal resistance of the cell.

A cell gives a balance with 85 cm of a potentiometer wire. When the terminals of the cell are shorted through a resistance of 7.5Omega , the balance is obtained at 75 cm. Find the internal resistance of the cell.

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shuntedd by a 5 Omega resistance, and is at a length of 3 m when the cell is shunted by a 10 Omega resistance. The internal resistance of the cell is, then

A potentiometer wire carries current. The potential difference across 70 cm of its balances the potential difference across a 2 ohm coil supllied by a cell of e.m.f. 2 volt. When a 1 ohm coil is placed in parallel with the 2 ohm coil, a length equal to 50 cm of the potentiometer wire is required to balance the potential difference across the parallel combination. What is the internal resistance of the 2 V cell?

A primary cell has an e.m.f. 1.5 volt. When short circuited, it gives a current of 3 ampere. The internal resistance of the cell is

In a potentiometer experiment , the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of 2Omega , the balancing length becomes 120 cm. Find the internal resistasnce of the cell.

In a potentiometer arrangement for determining the emf of a cell, the balance point of the cell in open circuit is 350 cm. When resistance of 9 Omega is used in the external circuit of the cell, the balance point shifts to 300 cm. Determine the internal resistance of the cell.

A cell of e.m.f E is connected across a resistance r. The potential differene between the terminals of the cell is found to be V. The internal resistance fo the cell must be

In an experiment to determine the internal resistance of a cell, the null point is obtained at 2 cm, when the cell is shnted by a resistance of 5Omega . When the cell is shunted by a resistance of 20Omega , the null point is obtained at 3 cm. Find the internal resistance of the cell.