A cell of e.m.f. 2 V and negligible internal resistance is connected to a potentiometer wire of resistance 10 Omega and length 4 m. The potential difference per unit length (potential gradient ) of the wire is

A cell of e.m.f. 4 V and of negligible internal resistance is connected in series with a potentiometer wire of length 400 cm. The e.m.f. of a Leelanche cell is found to be balacned at 150 cm from the positive end of the potentiometer wire. What is the e.m.f. of the Leclanche cell ?

A cell of emf 2 V and internal resistance 0.1Omega is connected to 3.9Omega external resistance. What will be the potential difference across the terminals of the cell?

A cell of e.m.f. 1.5 V and internal resistance 1Omega sends a current through wires of resistance 6Omega and 12Omega connected in parallel. Find the current through each wire.

Two batteries of e.m.f. 4V and 8V with internal resistances 1 Omega and 2 Omega are connected in a circuit with a resistance of 9 Omega as shown in figure. The current and potential difference between the points A and B

The potentiometer consists of a wire of length 4 m and resistance of 10Omega . It is connected to a cell of e.m.f. 2 V. The potential difference per unti length of the wire will be

The e.m.f of Daniel cell is 1.09 V and internal resistance is 2Omega . If the terminals of the cell are joined by a wire of resistance of 18Omega find the potential difference recorded by a higher resistance voltmeter also connected to the terminals of the cell.