Derive the expression for internal resistance of a cell.

Derive expression for the total resistance of a circuit in which a few resistors are connected in parallel.

In an experiment to determine the internal resistance of a cell, the null point is obtained at 2 cm, when the cell is shnted by a resistance of 5Omega . When the cell is shunted by a resistance of 20Omega , the null point is obtained at 3 cm. Find the internal resistance of the cell.

Three identical cells of emf 4V each and unknown internal resistances are connected in parallel.The combination is connected to 10 ohm resistor. If terminal voltage across the cells is 2V, find internal resistance of each cell.

Three identical cells of emf 4V each and unknown internal resistances are connected in parallel.The combination is connected to 10 ohm resistor. If terminal voltage across the cells is 2V, find internal resistance of each cell.

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shuntedd by a 5 Omega resistance, and is at a length of 3 m when the cell is shunted by a 10 Omega resistance. The internal resistance of the cell is, then

Define the term resistivity and write its S.I. unit. Derive the expression for the resistivity in terms of number density of free electrons and relaxation time.