A charge q moving in a straight line is accelerated by a potential difference V. It enters a uniform magnetic field B perpendicular to its path. Deduce in terms of V an expression for the radius of the circular path in which they travel?

A charged particle after being accelerated through a potential difference 'V' enters in a uniform magnetic field and moves in a circle of radius r. If V is the doubled, the radius of the circle will become

A charged particle moves thorugh a uniform magnetic field perpendicular to its direction. Then

An electron after bein accelerated through a potential difference of 1 00 V enters a uniform magnetic field of 0.004 T perpendiular to its direction of motion. Calculate the radius of the path describe by the electron. Given m = 9.1 xx 10^-31 kg and e = 1.6 xx 10^-19 C

A charge q of mass m moving with velocity v, at right angles to a uniform magnetic field B. Deduce the expression for the radius of the circular path it describes.

A particle with charge q moving with a velocity v in the plane of the paper enters a uniform magnetc field B, acting perpendicular to the plane of the paper. Deduce an expression for the tie period of the charge, as it moves in a circular path in the field. Why does the kinetic energy of the charge not change, while moving in the magnetic field?