A cyclotron is operated at an oscillator frequency of 12 MHz and has a dee radius R 50 cm. What is the magnitude of the magnetic field needed for a proton to be accelerated in the cyclotron?

A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil?

A cyclotron's oscillator frequency is 10MHz. What should be the operating magnetic field fro accelerating protons? If the radius of its dees is 60cm, what is the kinetic energy (in MeV) of the proton beam produced by the acceleration? (e- 1.60xx10^-19C,m_p=1.67xx10^-27kg, 1MeV=1.6xx10^-13J)

A circular coil of 50 turns and radius 0.2 cm carries a current of 12 A. Find magnetic field at the centre of the coil.

In a plane e.m. wave the electric field oscillates sinusoidally at a frequency of 2 xx10^10 Hz and amplitude 48 Vm^-1 . What is the magnitude of oscillating magnetic field?

A cyclotron is operating at a frequency of 12xx10^(6)Hz . Mass of deuteron is 3.3xx10^(-27) kg and its charge is 1.6xx10^(-19) C. To accelerate the deuterons, the magnetic induction of the field required is :

In a cyclotron to accelerate proton, the magnetic field is 15,000 gauss and radius of the dees is 15 cm. Calculate the energy of the proton beam and the frequency of the oscillator. Take e/m for proton to be 9,580.84 e.m.u g^-1 and mass of proton = 1.67 xx 10^-24 g