Each atom of an iron bar `(5cmxx 1cm xx 1cm) `has a magnetic moment `1.8xx10^(-23)Am^2.`Knowing that the density of iron is 7.78×10 ^3 kgm -3 , atomic weight is 56 amu and avogadro's number is 6.02×10^ 23What will be the magnetic moment of the bar in the state of magnetic saturation.

Each atom of an iron bar (5cmxx 1cm xx 1cm) has a magnetic moment 1.8xx10^(-23)Am^2. What will be the torque required to place this magnetised bar perpendicular to magnetic field of 15000 gauss? Density of iron = 7.8xx10^3kg//m^3, Atomic wt. of iron =56, Avogadro's number = 6.023xx10^(23)//gm mole.

A magnet weighs 75 g and its magnetic moment is 2xx10^-4 A m^2 . If the density of the material of the magnet is 7.5 xx 10^3 kg m^-3 , calculate the intensity of magnetisation.

Assme that each of copper atom has one free electron estimate the number of free electrons in 1 mg of copper. Given that atomic weight of copper 63.5 and Avogadro number = 6.02 xx 10^23 . What is the charge possessed by these free electrons?

A bar magnet has a magnetic moment of 10 A m^2 . If its magnetic length is 5 cm, calculate its pole strength.

The electron in the hydrogen atom is moving with a speed of 2.3 xx 10^6 ms^-1 in anorbit of raidisu 0.53 overset(@)A . Calculate the magnetic moment of the revolving electron.

A paramagnetic gas consists of atoms each with a dipole moment of 1.5 xx 10^-23 j T^-1 . The temperature of the gas is 27^@C and its number density is 2xx10^26 m^-3 . What is the maximum magnetisation of the sample possible, when it is placed in an external magnetic field?

Iron has a body centred cubic unit cell with the cell dimension of 286.65 pm. Density of iron ·is 7.87 g cm^(-3) Use this information to calculate Avogadro's number. (Atomic mass of Fe= 56.0 u)