Calculate the work done in rotating a bar magnet of magnetic moment `3 JT^-1` through an angle of `60^@` from its position along a magnetic field of strength `0.34 xx 10^-4T`

The work done in turning a magnet of magnetic moment M through an angle theta from the meridian is

Find the amount of work done in rotating a magnet through an angle theta against the torque acting due to uniform magnetic field. What happens to the work done?

Work done in turning a magnet of magnetic moment M by an angle 90^@ from the meridian is n times the corresponding work done to turn it through an angle of 60^@ . Find the value of n.

A short magnet of magnetic moment 2.0 Weber-metre is lying in a horizontal plane with its north pole pointing 60^(@) east of north. Find the net magnetic field at a point north of the magnet 0.2 m away from it. Horizontal component of earth's magnetic field = 0.3 xx 10^(-4) T.

A small coil of radius 0.002 m is placed on the axis of a magnet of magnetic moment 10^(5) JT^(-1) and length 0.1 m at a distance of 0.15 m from the centre of the magnet. The plane of the coil is perpendicular to the axis of the magnet. Find the force on the when a current of 2.0 A is passed through it.

What is the magnitude of axial field due to a bar magnet of length 5 cm at a distance of 50 cm from its mid-point if its magnetic moment is 0.40 Am^2 ?

A bar magnet has a magnetic moment of 10 A m^2 . If its magnetic length is 5 cm, calculate its pole strength.

A bar magnet of magnetic moment 200 A-m^(2) is suspended in a magnetic field of intensity 0.25 N//A-m . The couple required to deflect it through 30^(@) is

A short bar magnet of magnetic moment 0.9 JT^-1 is placed with its axis at 45^@ to a uniform magnetic field. If it experiences a torque of 0.063 J: Calculate the magnitude of the magnetic field.