A hollow charged conductor has a tiny hole cut into its surface. Show that the electric field in the hole is `(sigma//2epsilon_0)` `hatn` , where `hatn` is the unit vector in the outward normal direction, and `sigma` is the surface charge density near the hole.

Assertion : The total charge stored in a capaitor is zero. Reason : The electric field just outside the capacitor is sigma//epsilon_0 . Where sigma is the charge density

Show that the normal component of electrostatic field has a discontinuity from one side of a charged surface to another given by (E_2 - E_1) hatn= (sigma)/(epsilon_0) where hatn is a unit vector normal to the surface at a point and is the surface charge density at that point. (The direction of hat n is from side 1 to side 2.) Hence show that just outside a conductor, the electric field is sigma hatn // epsilon_0

Show that the electric field at the surface of a charged conductor is given bu vecE = sigma/epsilon_0 hatn , where sigma is the surface charge density and hatn is a unit vector normal to the surface in the outward direction.

Show that the normal component of electrostatic field has a discontinuity from one side of a charged surface to another given by (E_2 - E_1) hatn= (sigma)/(epsilon_0) where n is a unit vector normal to the surface at a point and is the surface charge density at that point. (The direction of hatn is from side 1 to side 2.) Hence show that just outside a conductor, the electric field is sigma hatn // epsilon_0 . Show that the tangential component of electrostatic field is continuous from one side of a charged surface to another.

A spherical conductor of radius 12 cm has a charge of 1.6 xx 10^-7C distributed uniformly on its surface. What is the electric field inside the sphere?

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux phi is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field. phi=ointvecE.vec(ds)=q/epsilon_0 If ointvecE.vec(ds)=0 over a surface, then

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux phi is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field. phi=ointvecE.vec(ds)=q/epsilon_0 If there is only one type of charge in the universe, then

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux phi is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field. phi=ointvecE.vec(ds)=q/epsilon_0 We have a Gaussian surface of radius R with Q at the centre, then

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux phi is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field. phi=ointvecE.vec(ds)=q/epsilon_0 The electric field at a point is

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux phi is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field. phi=ointvecE.vec(ds)=q/epsilon_0 A positive charge Q is uniformly distributed along the circular ring of radius R. A small test charge q is placed at the centre of te ring as shown.