A test charge q is made to move in the electric field of a point charge Q along two different closed paths. Fig. First path has sections along and perpendicular loop of the same area as the first loop. How does the work done compare in the two cases?

Show that the work done in moving a unit charge along a closed path is zero.

Prove that the work done in moving a unit charge along a closed path in an electric field is zero?

Two point charges q and -q is placed at a distance 2a apart.Calculate the electric field at a point P situated at a distance r along the perpendicular bisector of the line joining the charges. What is the electric field when r gtgt a ? Also, give the direction of electric field W.r.t. electric dipole moment? .

A charge q moving in a straight line is accelerated by a potential difference V. It enters a uniform magnetic field B perpendicular to its path. Deduce in terms of V an expression for the radius of the circular path in which they travel?

A particle of charge q is moving with velocity v in the presence of crossed electric field E and magnetic field B as shown. Write the condition under which the particle will continue moving along x-axis. How would the trajectory of the particle be affected if the electric field is switched off?

Lorentz Force: If a charge +q is moving in an electric field E, it experiences a force qE called Lorentz electric force.If the charge q is moving in a magnetic field vecB , it experiences a force (vecvxxvecB) called Lorentz magnetic force. If charge q is moving in a n electric field E as well as in magnetic field vecB simultaneously, the total force experience by the charge is the sum of these two forces and is called total Lorentz force. If the charge is q is moving perpendicular to the magnetic field B, the work done by the magnetic field is

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . When a charged particle q is moving with velocity vecv in a magnetic field vecB , the force is non-zero. It means.

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . If an electron and a proton having same momenta enter perpendicular to a magnetic field, then