Figure shows a potentiometer circuit for comparison of two resistances. The balance point with a standard resistor `R = 10 Omega` is found to be 58.3 cm, while that with the unknown resistance x is 68.5 cm. determine the value of X.

Figure 3.34 shows a potentiometer circuit for comparison of two resistances. The balance point with a standard resistor R = 10.0 Omega is found to be 58.3 cm, while that with the unknown resistance X is 68.5 cm. Determine the value of X. What might you do if you failed to find a balance point with the given cell of emf epsilon ? :

Figure shows potentionmeter circuit for comparison of two resistances. The balance point with a standard resistor R=10.0Ω is found to be 58.3 cm, while that with the unknown resistance X is 68.5 cm. Determine the value of X. What would you do if you failed to find a balance point with the given cell of emf E?

Figure shows a potentiometer circuit for comparison of two resistances. The balance point with a standard resistor R = 10 Omega is found to be 58.3 cm, while that with the unknown resistance x is 68.5 cm. What would you do, if you failed to find a balance point with the given cell E?

Figure 3.35 shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5 Omega is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell. :

The resistance in the left gap of a metre bridge is 10Omega and the balance point is 40 cm from the left end. Calculate the value of unknown resistance.

The resistance in the left gap of a metre bridge is 10Omega and the balance point is 40 cm form the left end. Calculate the value of the unknown resistance.

Two resistances are connected in the two gaps of a meter bridge. The balance point is 20 cm from the zero end. When a resistance 15 Omega is connected in series with the smaller of two resistance, the null point shifts to 40 cm. The smaller of the two resistance has the value.

A certain unknown resistance is connected in the left gap and a resistance box in the right gap of a metre bridge. By introducing a resistance of 10 Omega with the help of resistance box, the balance point is determined. If the balance point shift by 20 cm on increasing the resistance from the resistance box by 12.5 Omega Find the value of unknown resistance.

An unknown resistance R_(1) is connected is series with a resistance of 10 Omega. This combination is connected to one gap of a meter bridge, while other gap is connected to another resistance R_(2) . The balance point is at 50 cm Now , when the 10 Omega resistance is removed, the balanced point shifts to 40 cm Then the value of R_(1) is.