Figure shows a potentiometer circuit for comparison of two resistances. The balance point with a standard resistor `R = 10 Omega` is found to be 58.3 cm, while that with the unknown resistance x is 68.5 cm. What would you do, if you failed to find a balance point with the given cell E?

Figure shows a potentiometer circuit for comparison of two resistances. The balance point with a standard resistor R = 10 Omega is found to be 58.3 cm, while that with the unknown resistance x is 68.5 cm. determine the value of X.

Figure shows potentionmeter circuit for comparison of two resistances. The balance point with a standard resistor R=10.0Ω is found to be 58.3 cm, while that with the unknown resistance X is 68.5 cm. Determine the value of X. What would you do if you failed to find a balance point with the given cell of emf E?

Figure 3.34 shows a potentiometer circuit for comparison of two resistances. The balance point with a standard resistor R = 10.0 Omega is found to be 58.3 cm, while that with the unknown resistance X is 68.5 cm. Determine the value of X. What might you do if you failed to find a balance point with the given cell of emf epsilon ? :

The resistance in the left gap of a metre bridge is 10Omega and the balance point is 40 cm from the left end. Calculate the value of unknown resistance.

The resistance in the left gap of a metre bridge is 10Omega and the balance point is 40 cm form the left end. Calculate the value of the unknown resistance.

Figure 3.35 shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5 Omega is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell. :

In a meter bridge when the resistance in the left gap is 2 Omega and an unknown resistance in the right gap the balance point is obtained at 40 cm from the zero end. On shunting the unknown resistance with 2 Omega , find the shift of the balance point on the bridge wire

Figure shows a potentiometer with a cell of 2.0 V and internal resistance 0.40 Omega maintaining a potential drop across the resistor wire AB. A standard cell which maintains a constant emf of 1.02 V (for very moderate currents upto a few mA) gives a balance point at 67.3 cm length of the wire. To ensure very low currents drawn from the standard cell, a very high resistance of 600 k Omega is put in series with it, which is shorted close to the balance point. The standard cell is then replaced by a cell of unknown emf epsilon and the balance point found similarly, turns out to be at 82.3 cm length of the wire. What purpose does the high resistance of 600 kOmega have? :

Figure shows a potentiometer with a cell of 2.0 V and internal resistance 0.40 Omega maintaining a potential drop across the resistor wire AB. A standard cell which maintains a constant emf of 1.02 V (for very moderate currents upto a few mA) gives a balance point at 67.3 cm length of the wire. To ensure very low currents drawn from the standard cell, a very high resistance of 600 k Omega is put in series with it, which is shorted close to the balance point. The standard cell is then replaced by a cell of unknown emf epsilon and the balance point found similarly, turns out to be at 82.3 cm length of the wire. What is the value epsilon ? :

Figure 3.33 shows a potentiometer with a cell of 2.0 V and internal resistance 0.40 Omega maintaining a potential drop across the resistor wire AB. A standard cell which maintains a constant emf of 1.02 V (for very moderate currents upto a few mA) gives a balance point at 67.3 cm length of the wire. To ensure very low currents drawn from the standard cell, a very high resistance of 600 k Omega is put in series with it, which is shorted close to the balance point. The standard cell is then replaced by a cell of unknown emf epsilon and the balance point found similarly, turns out to be at 82.3 cm length of the wire. Would the circuit work well for determining an extremely small emf, say of the order of a few mV (such as the typical emf of a thermo-couple)? If not, how will you modify the circuit?: