A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the center of the magnet. The earth's magnetic field at the place is 0.36 G and the angle of dip is zero. If the bar magnet is turned around by `180^@`, where will the new null points be located?

A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null-point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)

A short bar magnet is placed in a horizontal plane with its axis in the magnetic merdian . Null points are found on its equitorial line (i.e., its normal bisector) at 12.5 cm and the earth's magnetic field at the place is 0.38 G the angle of dip is zero. (i) What is the total magnetic field at points on the axis of the magnet located by the same distance (12.5 cm) as the null-points from the centre? (ii) Locate the null points when the magnet is turned around by 180^(@) . Assume that the length of the magnet is negligible as compared to the distance of the null-point from the centre of the magnet.

Explain three magnetic elements of earth's magnetic field at a given place.

The ratio of vertical component to the horizontal component of earth's magnetic field at a given place is 1. What is the angle of dip at that place?

It is found that the neutral points lie along the axis of a magnet placed on a table. What is the orientation of the magnet w.r.t. the earth's magnetic field.

The horizontal component of earths's magnetic field at a place is 0.3 xx 10^-4T . If the angle of dip is 60^@ , what is the total earth's magnetic field?

The ratio of the horizontal component to the resultant magnetic field of earth at a given place is 1//sqrt2 . What is the angle of dip at that place?

The vertical component of the earth's magnetic field at a given place is sqrt3 times its horizontal component. If total intensity of earth's magnetic field at the place is 0.4G, find the vale of angle of dip