A telephone cable at a place has four long straight horizontal wires carrying a current of 1.0 A in the same direction east to west. The earth’s magnetic field at the place is 0.39 G, and the angle of dip is `35^@`. The magnetic declination is nearly zero. What are the resultant magnetic fields at points 4.0 cm below the cable?

A telephone cable at a place has four long straight horizontal wires carrying a current of 1.0 A in the same direction east to west. The earth’s magnetic field at the place is 0.39 G, and the angle of dip is 35^@ . The magnetic declination is nearly zero. What are the resultant magnetic fields at points 4.0 cm below and above the cable?

The horizontal component of earths's magnetic field at a place is 0.3 xx 10^-4T . If the angle of dip is 60^@ , what is the total earth's magnetic field?

The horizontal component of the earth's magnetic field at a place is B_H and angle of dip is 60^@ What is the value of vertical component of earth's magnetic field at equator?

A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null-point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)

The vertical component of the earth's magnetic field at a given place is sqrt3 times its horizontal component. If total intensity of earth's magnetic field at the place is 0.4G, find the vale of angle of dip

The ratio of vertical component to the horizontal component of earth's magnetic field at a given place is 1. What is the angle of dip at that place?

A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the center of the magnet. The earth's magnetic field at the place is 0.36 G and the angle of dip is zero. If the bar magnet is turned around by 180^@ , where will the new null points be located?