Home
Class 12
PHYSICS
In an a.c. circuit, the votlage applied ...

In an a.c. circuit, the votlage applied is `E = E_0 sin omegat` . The resultig current in the circuit is `I = I_0 sin (omegat - pi//2)`. The power consumption in the circuit will be

A

`E_0I_0//2`

B

`P=E_0I_0//sqrt2`

C

`P=sqrt2E_0I_0`

D

P=0

Text Solution

Verified by Experts

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • TEXTUAL QUESTIONS

    MODERN PUBLICATION|Exercise EXERCISE|507 Videos

  • STRUCTURE OF NUCLEUS

    MODERN PUBLICATION|Exercise EXERCISE|47 Videos

  • TEXUAL QUESTIONS

    MODERN PUBLICATION|Exercise EXERCISE|195 Videos

Similar Questions

Explore conceptually related problems

In an a.c. circuit, the current

In a.c. circuit, the power is consumed only in

Knowledge Check

  • For an inductor, the voltage applied E = E_(0) sin wt and resulting current is I = I_(0) sin(omega t - (pi)/(2)) . The power consumption in the circuit will be.

    A
    `(E_(0)I_(0))/(2)`
    B
    `(E_(0)I_(0))/(sqrt(2))`
    C
    `sqrt(2)E_(0)I_(0)`
    D
    0

  • For a circuit at resonacne, voltage applied is E = E_(0) sin wt and current is I = I_(0) sin wt, then power consumption in the circuit is :

    A
    `(E_(0)I_(0))/(2)`
    B
    `(E_(0)I_(0))/(sqrt(2))`
    C
    `sqrt(2)E_(0)I_(0)`
    D
    0

    • Similar Questions

    Explore conceptually related problems

    In an LCR-series a.c. circuit, the current

    A current I = I_0 sin (omegat + pi//2) flows in a circuit across which an alternating potential E = E_0 sin omega t is applied. The power consumed in the circuit is

    For a circuit at resonance, voltage applied is E = E_@ sin wt and current is I = I_@ sin wt, then power consumption in the circuit is :

    For a circuit at resonance, voltage applied is E = E_@ sin wt and current is I = I_@ sin wt, then power consumption in the circuit is :

    In an a.c. circuit, with phase voltage V and current I, the power dissipated is

    An alternating voltage E=E_0 sin omegat is applied to a circuit containing a resistor R connected in series with a black box. The current in the circuit is found to be I = I_0 sin(omegat+pi/4) . State whether the element in the black box is a capacitor or indutor.

    Home
    Profile