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A current I = I0 sin (omegat + pi//2) fl...

A current `I = I_0 sin (omegat + pi//2)` flows in a circuit across which an alternating potential `E = E_0 sin omega t` is applied. The power consumed in the circuit is

A

`E_0I_0//2`

B

`E_0I_0`

C

E

D

zero

Text Solution

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MODERN PUBLICATION-TEXTUAL QUESTIONS-EXERCISE
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