An LCR series circuit having 220 V ac source, inductance L = 25 mH and resistance R = 100 Omega. If voltage across inductor is just double of voltage across resistor then find out frequency of source.

A 50 Hz a.c. source of 20 V is connected across R and C as shown in figure. The voltage across R is 12 V. The voltage across C is

An alternating voltage given by E = 280 sin 50 pit is connected across pure resistor of 40 Omega . Find frequency of the source.

In an LCR-series a.c. circuit, the voltage across each of the components L,C and R is 50 V. The voltage across the LC-combination will be

A 220V-50hz a.c. source is connected to an inductance of 0.2 henry and a resistance of 20 ohm in series What is the current in the circuit?

In a series RC circuit, R = 30 ohm, C = 0.25 mu F, V = 100 V, omega = 10000 rad//s . Find the current in the circuit and calculate the voltage across the resistor and capacitor. Is the algebraic sum of these voltages more than the source voltage ? If yes, resolve the paradox.

In a series resonant circuit, the a.c. voltage across resistance R, inductance L and capacitance C are 5 V. 10 V and 10 V respectively. The a.c. voltage respetively. The a.c. voltage applied to the circuit will be

In a LCR series circuit, the potential difference between the terminals of the inductance is 60 V, between the terminals of the capacitor is 30 V nd that across the resistance is 40 V. Then, then supply voltage will be equal to

Figure shows a series LCR circuit connected to a variable frequency 230 V source. L = 5.0 H, C = 80 muF , R= 40 Omega . Obtain the impedance of the circuit and the amplitude of current at the resonating frequency. :

An a.c. source of 100 V (r.m.s.), 50 Hz is connected across a 20 ohm resistance and a 50 mH inductor in series Calculate r.m.s. current in the circuit.