A parallel plate cpacitor has plates of area `0.32 m^2` ,which are separated by a distance of 5mm.The capacitor is raised to a potential of 1,200 V.Estimate the average value of displacement current,when it is discharged for 1 `mus`.

A parallel plate capacitor thas plates of are 0.02m^2 and separation between the plates 1 mm. What potential difference will be developed, if a charge of 1nC is given to the capacitor ? If the plate separation is now increased to 2 mm, what will be the new potential difference?

The plates of a parallel plate capacitor have an area of 90 cm^2 each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply. (a) How much electrostatic energy is stored by the capacitor? (b) View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume u. Hence arrive at a relation between u and the magnitude of electric field E between the plates.

The plates of a parallel plate capacitor have an area of 90 cm^2 each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply. How much electrostatic energy is stored by the capacitor?

A parallel-plate capacitor having plate are 100 cm ^2 and separation 1.0 mm holds a charge of 0.12 muC when connected to a 120 V battery. Find the dielectric constant of the material filling the gap.

A parallel plate capacitor has two plates of sides 0.055 m and 0.04 m of air. Their distance apart is 0.7 mm. The dielectric constant of the medium in between is 4. Find the capacitance of the capacitor.

Two plates of parallel plate capacitor have an area of 90 cm^2 (centimeter square) each and are separated by 2.5 mm. The capacitor is charged by Connecting it to a 400V (volt) supply. How much electrostatic energy is stored by the capacitor ?

A capacitor is charged through a potential difference of 200 V, when 0.1 C charge is stored in it. How much energy will it release, when it is discharged?

A parallel plate capacitor has plates of area A separated by distance ‘d’ between them. It is filled with a dielectric which has dielectric constant that varies as K (y) = k _(0) (1+ alpha y) where ‘y’ is the vertical distance measured from base of the plates. The total capacitance of the system is best given by: (K _(0) is constant)