A convex lens is made of glass of refractive index 1.5.If radius of curvature of the each of its twosurfaces is 20 cm,find the ratio of the power of the lens,when placed in air to its power ,when immersed inside a liquid of refractive index 1.25.

A convex lens is made of glass of refractive index 1.5. If radius of curvature of the each of its two surfaces is 20 cm, find the ratio of power , of lens when placed in air to its power, when immersed inside a liquid of refractive index 1.25 .

A plano-convex lens is made of refractive index 1.6.If the radius of curvature of the curved surface is 60 cm,then focal length of the lens is:

What happens when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3?

Explain what happens ,when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3.

A plano-convex lens is made of a material of refrative index mu=1.5 .The radius of curvature of curved surface of the lens is 20 cm.If its plane surface is silvered,the focal length of the silvered lens will be

A double convex lens made of glass of refactive index 1.56 has both radii of curvature of magnitude 20 cm.If an object is placed at a distance of 10 cm from this lens,find the positiojn of the image formed.

Find the ratio of the powers of a glass lens in water and in air .Given,refractive index of glass =1.50,refractive index of water=1.33.

Focal length of a convex lens of refractive index 1.5 is 2 cm.Focal length of lens,when immersed in a liquid of refractive index of 1.25 will be

A converging lens has a focal length of 20 cm in air. It is made of a material of refractive index 1.6. If it is immersed in a liquid of refractive index 1.3, what will be the new focal length? How does the nature of the lens change. If this lens is immersed is a liquid of refractive index 1.8 ?