Light is incident on a thin lents a shown in Fig.2.68.The radius of curvature for both the surfaces is R.Determine the focal length of this system.
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A plano-convex lens is made of refractive index 1.6.If the radius of curvature of the curved surface is 60 cm,then focal length of the lens is:

What is the focal length of a double convex lens for which radius of curvature of the surfaces is 40 cm and refractive index of the glass is 1.5?

A plano-convex lens is made of a material of refrative index mu=1.5 .The radius of curvature of curved surface of the lens is 20 cm.If its plane surface is silvered,the focal length of the silvered lens will be

Double-convex lenses are to be manufactured from a glass of refractive index 1.55, with both faces of the same radius of curvature. What is the radius of curvature required if the focal length is to be 20cm?

A binovex lens has a focal lenth 2//3 tiems the radius of curvature of either surface.Calculate the refractive index of lens material.

An equiconvex lens with radii of curvature of magnitude R each,is put over a liquid layer poured on top of a plane mirror.A small needle ,with its tip on the principal axis of the lens,is moved along the axis until its inverted real image coincides with the needle itself.The distance of the needle from the lens is measured to be a as shown in Fig.2.53. On removing the liquid layer and repeating the ezperiment,the distance is found to be b as shown in Fig.254 .Gien that tow values of distances meeawured reepresent the focal length values in the two cases, obtain a formula for the refractive index of the liquid. .

A beam of light of wavelength 400 nm is incident normally on a right angled prism as shown in fir.2.45. . It is observed that the light just grazes long the surface AC after falling on it.Give that there fractive index of the material of the prism varies with the wavelength as per the relation. mu=1.2 + b/(gamma^2) Calculate the value of b and the refractive index of the prism material for a wavelength gamma = 500 nm .Given theta=sin^(-1) 0.625 .