The focal lengths of the objective and eye-piece of a compound microscope are 4 cm and 6 cm respectively. If an object is placed at a distance of 6 cm from the objective, what is the magnification produced by the microscope? Distance of distinct vision = 25 cm.

The focal lengths of the objective and eye-piece of a compound microscope are 1.25 cm and 5 cm respectively. Find the position of the object relative to the objective in order to obtain an angular magnification of 30 in normal adjustment.

When an object is placed at a distance of 60 cm from a convex spherical mirror, the magnification produced is 1//2 .Where should the object be placed to get a magnification of 1//3 ?

The focal length of the objective and eye piece of a telescope are respectively 200 cm and 5 cm.the maximum magnifying power of the telescope will be

A telescope has focal elngth of objective and eyepiece as 200 cm and 5 cm respectively.what is magnification of telescope?

A concave mirror has a focal length of 20 cm and an object is placed at a distance of 16 cm from it.Find the position of the image formed by it.

A concave mirror has a focal length of 10 cm and an object is placed at a distance of 16 cm from it.Find the psition of the image formed by it.

The focal length of th eye-piece and ojective a compound microscope are 5 cm and 1 cm respectively and the length of the tube is 20 cm.Calculate he magnifying power of the microscope,when the final image is formed at infinity .The value of least distance of ditinct vision is 25cm.