The magnifying power an astronomical telescope in the normal adjustment position is 100. The distance between the objective and the eyepiece is 101 cm. calculate the focal length of the objective and the eyepiece.

The magnifying power of an astronomical telescope in the normal adjustment position is 20.If the length of the telescope is 105 cm in this adujustment ,find the focal lengths of the two lenses.

What is the magnifying power of an astronomical telescope in normal adjustment? What is its length?

An astronomical telescope,when in normal adjustment has magnifying power 5.If the distance between two lenses is 24 cm,find the focal length of both the lenses.

If the distance between the screen and object is 50 cm and the displacement of the lens is 10 cm,clculate the focal length of the lens.

The astronomical telescope consists off objective and eye-piece.The focal length of the objective is

What is the magnifying power of an astronomical telescope when the final image of a distant object is formed at least distance of distinct vision?

Answer the following questions: Why must both the objective and the eyepiece of a compound microscope have short focal lengths?

The total magnification produced by a compound microscope is 20,while that produced by the eye-piece alone is 5.When the microscope is focussed on a certain object,the distance between objective nad eye-piece is 14 cm.Find the focal length of objective and eye-piece,if distance of distinct vision is 20 cm.

What is the distance between object and eye lens, when the telescope is on normal adjustment?