In a Young's double slit experiment,interfernce fringes were produced on a screen placed at 1.5 m from the two slits 0.3 mm apar and illuminated by ligth of `6,400 overset@A`.Find the fringe width.

In a Young's double slit experiment,two slits are 1.5 mm apart and a screen in placed at a distance 1.2 m from the plane of the slits .The slits are illuminated with light of wavelength 6,000 overset @A .Find the inimum distance from the central maximum for which the intensity is half of the maximum intensity.

In Young's double slit experiment,the slits are 0.2 mm apart.The interfernce fringes for ligth of wavelength 6,000 overset @A are formed on a screen distanct 1.5 m from the sits.Calculate the fringe width.

A light of wavelength 1300 A^@ is used to illuminate two slits as a distance of 0.3 mm apart in Young.s double slit experiment. Fringes observed on a screen are found to be 1.3 mm apart. Find the distance of screen from the slits and also find the fringe width if the distance of screen is doubled now.

Tick the correct option: In Young's double slit experiment the fringe width beta is :

Young's double - slit experiment for interference is performed with two slits 3xx 10^(-3) m apart and light of wavelength 6,600 overset @A . If the screen is 1 m away from the slits,find out the position of the fourth dark fringe.