In a simple slit diffraction experiment,first minimum of rd light(660 nm) coincides with first maximum of some other wavelength `lambda'`. Find the value of `lambda'`.

In a single slt diffraction experiment,the thrid minimum due to red light of wavelength 720 nm coinciedes with the fourth maximum due to ligth of some unkown wavelength.Find the value of the unkown wavelength.

For a single slit of width a ,the first minimum of the interference pattern of a monochromatic ligth of wavlength lambda .occurs at an angle of lambda//a .At the same angle of lambda//a ,we get a maximum for two narrow sits separated bby a distance a.Explain.

In the diffraction of a single slit experiment, how would the width of and the intensity of central maximum change,if visible light of longer wavelength is used?

Diffraction of light Diffraction of light is the phenomenon of bending of light round corners of an obstacle or aperture and spreading into the geometraicl shadow of the diffracting object. The condition for diffractio of light is the size of the aperature should be comparable to the wavelength of incident light. so in daily life, we find that diffraction of sound is more common than the diffraction of light. width of central maxima is {formula= ((2lambdaD)/d) } In single slit diffraction experiment, if the width of the slit is doubled, if the intensity of central fringe diffraction band becomes.

In Young's double slit experiment,usin light of wavelength 400 nm,interference fringes of width X are obtained .The wavelength of light is increassed to 600 nm and the separation between the slits is halved.If one wants the observed fringe width on the screen to be the same in the two caes,find the rati of the distance between the screen and the plane of the interfering sources in the two arrangements.

A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes in a Young experiment.- Find the distance of the third bright fringe on the screen from the central maximum for wavelength 650 nm.

In a Young's double slit experiment,the separation betwen the two slits is d and the wavelength of the light is lambda .The intensity of light falling on the slit 1 is four times the intesntiy of light falling on slit 2.Choose the correct choice(s).

In a Young's double slit experiment,the intensity at a point,where the path difference is lambda//6 ( lambda being the wabelength of the light used) is I .If I_0 denotwes the maximum intensity,then I//I_0 is equal to

In an ideal double slit experiment when a glass plate having refractive index 1.5 and thickness t is placed in the path of interfered light rays of wavelength lambda then the intensity remains unchanged at the place where the central maximum was previously formed. Then the minimum thickness of the glass plate is

A parallel monochromatic beam of light is incident normally on a narrow slit.A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam.At the first minimum of the diffraction pattern,the phase difference between the rays coming from the two edges of the slit is