In a head on collision between an alpha particle and a gold nucleius (Z=79),the distnace of closet approach is 39.5 fermi.Calculate the enrgy of alpha particle.

An alpha particle (_2He^4) is moving directly towards a stationary gold nucleus (_(79)Au^(197)) .The alpha -particle and the gold nucleus may be considered to be solid spheres with the charge and mass concentrated at the centre of each sphere.When the two spheres are just toching,the sepaation of their centres is 9.6 xx 10^(-15) m . the alpha particle and the gold nucleus may be assumed to be an isolatedd system.Calculate for the alpha particle just in contact with the gold nucleus, its electric potential energy.

When a deuton of mass 2.0141 u and neglible kinetic energy is absorbed by lithium ("_3^6Li) of nucleus of mass 6.0155 u, the compound nucleus disintegrates spontaneously into two alpha particles, each of mass 4.0026u. Calculate the energy in joules by each alpha particle. (1u=1.66 xx 10^-27kg)

Calculate the Coulomb.s force between two alpha particles separated by a distance of 3.2xx10^-15m

In Geiger-Marsden experiment,a 5 MeV alpha -particle is scattered through 180^@ from the gold foil.If the atomic number of gold is 79 ,find the distance of closet appraoch to the gold nucleus.

The distance of closest approach of an alpha particle gives an estimate of the size of the nucleus. Explain

An alpha particle having kinetic energy equal to 8.7 MeV is projected towards the nucleus of copper with Z=29.Calculate its distance of closet approach.

The nucleus of an atom of ._(92)Y^(235) initially at rest decays by emitting an alpha particle. The binding energy per nucleon of parent and dougther nuclei are 7.8MeV and 7.835MeV respectively and that of alpha particles is 7.07MeV//"nucleon". Assuming the dougther nucleus to be formed in the unexcited state and neglecting its share of energy in the reaction, calculate speed of emitted alpha particle. Take mass of alpha particle to be 6.68xx10^(-27)kg .

A deuteron and an alpha particle having same momentum are in turn allowed to pass through a magnetic field B, acting normal to the direction of motion of the particles. Calculate the ratio of the radii of the circular paths described by them.

A nucleus at rest undergoes a decay emitting an alpha -particle of de-broglie wavelength lambda = 5.76 xx 10^(-15) m . The mass of daughter nucleus is 223.40 amu and that of alpha-particle is 4.002 a.m.u.detrmine the total kinetic energy in the final state.Hence,obtain teh mass of the parent nucleus in a.m.u. Given that 1 a.m.u.=931.470 MeV .