Consider the decay of the free neutron at rest:
n = p + `e^-`.
Show that the two-body decay of this type must necessarily give an electron of fixed energy and, therefore, cannot account for the observed continuous energy distribution in the `beta` decay of a neutron or a nucleus.

What is the basic mechanism for the emission of beta^(-) or beta^(+) particles in a nucleide? Give an example by writing explicity a decay process for beta^(-) emission. Is (a) the energy of the emitted beta -particles continuous or discrete, the daughter nucleus obtained through beta -decay, an isotope or an isobar of the parent nucleus?

Deutron is a bound state of a nuetron and a proton with a binding energy B=2.2 MeV. A gamma-rays of energy E is aimed at a deuteron nucleus to try to break it into a (neutron+proton) such that the n and p move in the direction of the incident gamma-rays . If E=B, show that this cannot happen. Hence calculate how much bigger than B must E be for a such a process to happen.

Each question contains STATEMENTS-1 (Assertion) and STATEMENT -2 (Reason). Examine the statements carefully and mark the correct answer according to the instructions given below: STATEMENT-1: Nucleus does not contain fee electrons, yet it emit beta-particles STATEMENT-2: At high n/p ratio, one neutron supposed to give 1 proton and 1 e^(-)(beta) .