The current in the forward bias is known to be more `(~mA)` than the current in the reverse bias `(~muA)`. What is the reason then to operate the photodiodes in reverse bias?

Draw a PN-Junction with reverse bias.

In the figure the emitter forward bias or reverse bias?

What is reverse current due to?

What happens if forward bias is made very high?

In a transistor, forward bias is always small as compared to the reverse bias. Why?

A straight segment OC(of length L meter) of a circuit carrying a current I amp is placed along the x- axis ( fig.). Two infinitely long straight wires A and B , each extending from z = -oo to +oo , are fixed at y = -a meter and y = +a meter respectively, as shown in the figure. If the wires A and B each carry a current I amp into the plane of the paper, obtain the expression for the force acting on the segment OC. What will be the force on OC if the current in the wire B is reversed?

In a p-n junction diode, the current I can be expressed as I = I_0 (exp ((eV)/(2k_BT))-1) where I_0 is called the reverse saturation current, V is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, k_B is th Boltzmann constant (8.6xx 10^-5 eV/K) and T is the absolute temperature. If for a given diode I_0 = 5 xx 10^ -12 A and T = 300 K, then - What will be the current if reverse bias voltage changes from 1 V to 2 V?

In a p-n junction diode, the current I can be expressed as I = I_0 (exp ((eV)/(2k_BT))-1) where I_0 is called the reverse saturation current, V is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, k_B is th Boltzmann constant (8.6xx 10^ -5 eV/K) and T is the absolute temperature. If for a given diode I_0 = 5 xx 10^ -12 A and T = 300 K, then - What will be the forward current at a forward voltage of 0.6 V?