The diemnsion of energy density,`1/2 epsilon_0 E^2`, where `elipson_0` is permittivity of free space and E is electric field is :

The unit of permittivity of free space (E_0) is :

Find the capacitance of a system of three parallel plates each of area A metres^2 separated by distane d_1 and d_2 metre respectively. The space between them is filled with dielectris of relative constants epsilon_1 and epsilon_2 . The permittivity of free space is ε 0 The equivalent capacitance of the system is:

Using the concept of free electrons in a conductor, derive the expression for the conductivity of a wire in terms of number density and relaxation time. Hence obtain the relation between current density and the applied electric field E.

Show that the energy density of em radiation is epsilon_0E^2 . Hence, find the intensity of radiations?

Dimensions of 1/(mu_0epsilon_0) , where symbols have their usual meanings are:

Show that the normal component of electrostatic field has a discontinuity from one side of a charged surface to another given by (E_2 - E_1) hatn= (sigma)/(epsilon_0) where n is a unit vector normal to the surface at a point and is the surface charge density at that point. (The direction of hatn is from side 1 to side 2.) Hence show that just outside a conductor, the electric field is sigma hatn // epsilon_0 . Show that the tangential component of electrostatic field is continuous from one side of a charged surface to another.

Show that the normal component of electrostatic field has a discontinuity from one side of a charged surface to another given by (E_2 - E_1) hatn= (sigma)/(epsilon_0) where hatn is a unit vector normal to the surface at a point and is the surface charge density at that point. (The direction of hat n is from side 1 to side 2.) Hence show that just outside a conductor, the electric field is sigma hatn // epsilon_0

Dimensions of (mu_(0) epsilon_0)^(-1/2) are :

Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (1/2) QE, where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor 1/2.

Show that the electric field at the surface of a charged conductor is given bu vecE = sigma/epsilon_0 hatn , where sigma is the surface charge density and hatn is a unit vector normal to the surface in the outward direction.