An electron microscope uses electron accelerated by a voltage of 50kV. Determine the de-Broglie wavelengths associated with the electrons. If other factors (such as numerical aperture etc) are taken to be roughly the same how does the resolving power of electron microscope compare with that of an optical microscope which uses yellow light?

How does the resolving power of a compound microscope change of decreasing the wave length of light used,and

A electron is accelerated through a potential difference of 100V. What is de-Broglie wavelength associated with it? To which part of the electromagnetic spectrum does this value of wavelength correspond?

An electron and alpha particle have the same de-Broglie wavelength associated with them. How are their kinetic energies related to each other?

Define resolving power of a compound microscope. How does the resolving power of a compound microscope change when wavelength of radiation used is increased.

The wavelength of light the spectral emission line of sodium is 589 nm. Find the kinetic energy at which (a) an electron and (b) a neutron,would have the same de Broglie wavelength.

Werner Heisenberg considered the limits of how precisely we can measure the properties of an electron or other microscopic particle. He determined that there is a fundamental limit to how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse also true. This is summed up in what we now call the Heisenberg uncertainty principle. The equation si deltax.delta (mv)ge(h)/(4pi) The uncertainty in the position or in the momentum of a marcroscopic object like a baseball is too small to observe. However, the mass of microscopic object such as an electon is small enough for the uncertainty to be relatively large and significant. What would be the minimum uncetaintty in de-Broglie wavelength of a moving electron accelerated by potential difference of 6 volt and whose uncetainty in position is (7)/(22) nm?

Werner Heisenberg considered the limits of how precisely we can measure the properties of an electron or other microscopic particle. He determined that there is a fundamental limit to how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse also true. This is summed up in what we now call the Heisenberg uncertainty principle. The equation si deltax.delta (mv)ge(h)/(4pi) The uncertainty in the position or in the momentum of a marcroscopic object like a baseball is too small to observe. However, the mass of microscopic object such as an electon is small enough for the uncertainty to be relatively large and significant. If the uncertainty in velocity and position is same, then the uncertainty in momentum will be :