Two monochromatic beams A and B of equal intensity I, hit a screen. The number of photons hitting the screen by beam A is twice than by beam B. then what inference can you make about their frequencies?

A monochromatic beam of light is used for the formation of fringes on the screen by illuminating the two slits in the Young's double slit interference experiment. When a thin film of mica is interposed in the path of one of the interfering beams, then

Two beams of light having intensities I and 4 I interfere to produce a fringe pattern on a screen.The phase difference between the beams is pi//2 at point A and pi at point B.Then the differnece between the resultant intensities at A and B is

A parallel monochromatic beam of light is incident normally on a narrow slit.A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam.At the first minimum of the diffraction pattern,the phase difference between the rays coming from the two edges of the slit is

Given that the product of two rational numbers is rational, and suppose a and b are rationals, what can you conclude about ab ?

A beam of light consisting of two wavelegnths, 6,500 overset @A and 5,200 overset @A is used to obtain interference fringes in a Young's double slit experiment. The distance between the slits is 2 mm and the screen is 120 cm. What is the least distance from the central maximum, when the bright fringes due to both the wavelengths coincide?

A beam of ligth consisting of two wavelength 4,800 overset@A and 6,000 overset@A is used to obtain interfernce fringes in a double slit experiment.The distnce between the slits is 1.8 mm and the distance of screen from the plane of slits is 1.2 m What is the lest distance from the centre of the screen,where the brigth fringes due to both the wvelength coincide?

Estimating the following numbers should be interesting. The number tells you why our eye can never count photons, even in barely detetable light. The number of photons entering the pupil of our eye per second corresponding to the minimum intensity of white light that we humans can perceive (~10^-10 Wm^-2) . Take the area of the pupil to be about 0.4 cm^2 , and the average frequency of white light to be about 6 xx 10^14 Hz .

A company manufactures two types of sweaters type A and type B. If costs Rs. 360 to make a type A screws Rs.120 to make a type B sweater. The company can make if at most 300 sweaters and spend at most Rs.72000 a day. The number of sweaters of type B cannot exceeds number of sweater of type A by more than 100. the company makes it a profit of Rs.200 for each sweater of type A and Rs.120 for every sweater of type B. formulate this problem as an LPP to maximise to profit to the company. also solve this LPP to find the maximum profit.

Light from an ordianry source(say a sodium lamp) is passed through a polaroid sheet P_1 .The transmitted light is then made to pass through a second polaroid sheet P_2 ,which can be rotated so that the angle (theta) betwen the two polaroid sheets varies from 0^@ to 90^@ .Show graphically the variation of he intensity of light transmitted by P_1 and P_2 as a function of the angle theta .Take the incident beam intensity as I_0 . Why does the light from a cleear blue portion of the sky,show a rise and fall on intesnity,when viewed through a polaroid ,which is rotated?

If hydrogen atoms (in the ground state ) are passed through an homogeneous magnetic field, the beam is split into two parts. This interaction with the magnetic field shows that the atoms must have magnetic moment. However, the moment cannot be due to the orbital angular momentum since l=0. Hence one must assume existence of intrinsic angular momentum, which as the experiment shows, has only two permitted orientations. Spin of the electron produce angular momentum equal to S=sqrt(s(s+1))(h)/(2pi) where S=+(1)/(2) . Total spin of an atom = +(n)/(2) " or "-(n)/(2) where n is the number of unpaired electrons. The substance which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. The paramagnetism is expressed in terms of magnetic moment. The magnetic moment of an atom mu_(s)sqrt(s(s+1))(eh)/(2pimc)=sqrt((n)/(2)((n)/(2)+1))(eh)/(2pimc)" "s=(n)/(2) impliesmu_(s)=sqrt(n(n+1)) B.M. 1. B.M. (Bohr magneton)= (eh)/(4pimc) If magnetic moment is zero the substance is diamagnetic. If an ion of _(25)Mn has a magnetic moment of 3.873 B.M. Then oxidation state of Mn in ion is :